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u^2-33u+200=0
a = 1; b = -33; c = +200;
Δ = b2-4ac
Δ = -332-4·1·200
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-33)-17}{2*1}=\frac{16}{2} =8 $$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-33)+17}{2*1}=\frac{50}{2} =25 $
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